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Pasted as Bash by bliznezz ( 12 years ago )
for P in {24..1} ; do  TIME="${P} %E\\t %e\\t %S\\t %U" time  pbzip2 -c -p${P} example_4gb > /dev/null  ; done
#
#    первый столбец - колво используемых ядер cpu. 
#
#       %E     Elapsed real time (in [hours:]minutes:seconds).
#       %e     (Not in tcsh.) Elapsed real time (in seconds).
#       %S     Total number of CPU-seconds that the process spent in kernel mode.
#       %U     Total number of CPU-seconds that the process spent in user mode.
#
# это значит строка с  P=24  
#  24  0:04.59       4.59    2.62    99.58
# в привычной записи time даёт результат: 
#  real    0m4.59s
#  user    1m39r.58s   (99.58 сек)
#  sys     0m2.62s



24 0:04.59       4.59    2.62    99.58
23 0:04.47       4.47    2.49    97.32
22 0:04.51       4.51    2.41    94.58
21 0:04.61       4.61    2.42    92.53
20 0:04.66       4.66    2.32    90.93
19 0:04.61       4.61    2.17    85.68
18 0:04.72       4.72    2.12    82.95
17 0:04.82       4.82    2.07    79.70
16 0:04.91       4.91    2.10    77.13
15 0:05.07       5.07    1.90    74.67
14 0:05.06       5.06    1.93    69.25
13 0:05.41       5.41    2.16    68.85
12 0:05.42       5.42    1.96    63.91
11 0:05.61       5.61    1.74    60.90
10 0:06.36       6.36    1.89    62.65
9 0:06.77        6.77    1.61    59.96
8 0:07.62        7.62    1.68    60.13
7 0:08.67        8.67    1.92    59.92
6 0:10.02        10.02   1.82    59.20
5 0:12.02        12.02   1.73    59.29
4 0:14.78        14.78   1.38    58.47
3 0:19.99        19.99   1.43    59.09
2 0:29.21        29.21   1.40    57.81
1 0:59.13        59.13   1.34    57.77

 

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